The time period of oscillation of simple pendulum is given by t = 2pisqrt(I//g) What is the accurancy in the determination of 'g' if 10cm length is knownj to 1mm accuracy and
2. T 20 (t),h = 0.5, m = 10, θ = π/10. | Download Scientific Diagram
A wheel with 10 metallic spokes each 0.5mHong is rotated with a speed of 120 rev/min in a planenormal to the earth's magnetic field at the place. Ifhe magnitude of the field
The period of oscillation of a simple pendulum is `T = 2 pi sqrt((L)/(g)) .L` is about `10 cm` a... - YouTube
π Calculus I Problem Set 11 Answers Answer
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A rectangular loop of width a = 2 cm and length b = 4 cm is located near a long wire carrying a current I = 0.5 A shown in the figure
Two identical particles each of mass `0.5kg` are interconnected by a light springs of stiffness `100N//m`, time period of small oscillation is …. - Sarthaks eConnect | Largest Online Education Community
NCERT Q6 - A copper wire has diameter 0.5 mm and resistivity of 1.6